Contents Eurocode 2 04 RC PN 001

User Manual: Eurocode 2-04 RC-PN-001

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Software Verification
PROGRAM NAME:
REVISION NO.:

SAFE
0

EXAMPLE EUROCODE 2-04 RC-PN-001
Slab Punching Shear Design
PROBLEM DESCRIPTION
The purpose of this example is to verify slab punching shear design in SAFE
The numerical example is a flat slab that has three 8-m spans in each direction, as
shown in Figure 1.
0.3 m

A

B
8m

C
8m

D 0.3 m
8m

0.6 m

4
0.25 m thick flat slab
8m

3
Columns are 0.3 m x 0.9 m
with long side parallel
to the Y-axis, typical

8m

Concrete Properties
Unit weight = 24 kN/m3
f'c = 30 N/mm2

2
8m

Y
X

1

Loading
DL = Self weight + 1.0 kN/m 2
LL = 4.0 kN/m2

0.6 m

Figure 1: Flat Slab for Numerical Example

The slab overhangs beyond the face of the column by 0.15 m along each side of
the structure. The columns are typically 0.3 m x 0.9 m with the long side parallel
to the Y-axis. Thick plate properties are used for the slab.
The concrete has a unit weight of 24 kN/m3 and a f 'c of 30 N/mm2. The dead load
consists of the self weight of the structure plus an additional 1 kN/m2. The live
load is 4 kN/m2.

EXAMPLE EUROCODE 2-04 RC-PN-001 - 1

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TECHNICAL FEATURES OF SAFE TESTED
 Calculation of punching shear capacity, shear stress and D/C ratio.
RESULTS COMPARISON
Table 1 shows the comparison of the punching shear capacity, shear stress ratio
and D/C ratio obtained from SAFE with the punching shear capacity, shear stress
ratio and D/C ratio obtained by the analytical method. They match exactly for
this problem.
Table 1 Comparison of Design Results for Punching
Shear at Grid B-2
National Annex

CEN Default, Norway,
Slovenia and Sweden

Finland, Singapore and UK

Denmark

Method

Shear
Stress
(N/mm2)

Shear
Capacity
(N/mm2)

D/C
ratio

SAFE

1.100

0.578

1.90

Calculated

1.099

0.578

1.90

SAFE

1.100

0.5796

1.90

Calculated

1.099

0.5796

1.90

SAFE

1.100

0.606

1.82

Calculated

1.099

0.606

1.81

COMPUTER FILE: EUROCODE 2-04 RC-PN-001.FDB
CONCLUSION
The SAFE results show an acceptable comparison with the independent results.

EXAMPLE EUROCODE 2-04 RC-PN-001 - 2

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HAND CALCULATION
Hand Calculation for Interior Column using SAFE Method
d=

[( 250 − 26 ) + ( 250 − 38)]

2 = 218 mm

Refer to Figure 2.
u 1 = u = 2•300 + 2•900 + 2•π•436 = 5139.468 mm
1172

Note: All dimensions in millimeters
Critical section for
punching shear
shown dashed.

Y
436

150 150 436
B

A

Column

436

Side 3

Side 1

Side 2

450

X

1772

450

Center of column is
point (x1, y1). Set
this equal to (0,0).

436

Side 4
D

C

Figure 2: Interior Column, Grid B-2 in SAFE Model
From the SAFE output at Grid B-2:
V Ed = 1112.197 kN
k 2 M Ed2 = 41.593 kN-m
k 3 M Ed3 = 20.576 kN-m

EXAMPLE EUROCODE 2-04 RC-PN-001 - 3

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Maximum design shear stress in computed in along major and minor axis of column:
VEd  k2 M Ed ,2u1 k3 M Ed ,3u1 
+
vEd =
1 +

ud 
VEdW1,2
VEdW1,3 

(EC2 6.4.4(2))

c2
W1 = 1 + c1c2 + 4c2 d + 16d 2 + 2π dc1
2
W1,2
=

9002
+ 300 • 900 + 4 • 300 • 218 + 16 • 2182 + 2π • 218 • 900
2

W1,2 = 2,929, 744.957 mm2

3
W
=
1,3

9002
+ 900 • 300 + 4 • 900 • 218 + 16 • 2182 + 2π • 218 • 300
2

W1,2 = 2, 271,104.319 mm2

VEd  k2 M Ed ,2u1 k3 M Ed ,3u1 
vEd =
+
1 +

u1d 
VEdW1,2
VEdW1,3 

1112.197 • 103 
41.593 • 106 • 5139.468
20.576 • 106 • 5139.468 
1
vEd =
+
+


5139.468 • 218  1112.197 • 103 • 2929744.957 1112.197 • 103 • 2271104.319 
vEd = 1.099 N/mm2
Thus v max = 1.099 N/mm2
For CEN Default, Finland, Norway, Singapore, Slovenia, Sweden and UK:
C Rd ,c = 0.18 γ c = 0.18/1.5 = 0.12

(EC2 6.4.4)

For Denmark:
CRd ,c = 0.18 γ c = 0.18/1.45 = 0.124

(EC2 6.4.4)

The shear stress carried by the concrete, V Rd,c , is calculated as:
13
VRd ,c C Rd ,c k (100 ρ1 fck ) + k1σ cp 
=

(EC2 6.4.4)

with a minimum of:
v=
Rd ,c

(v

min

+ k1σ cp )

EXAMPLE EUROCODE 2-04 RC-PN-001 - 4

(EC2 6.4.4)

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k=
1+

200
≤ 2.0 = 1.9578
d

k1

= 0.15.

ρ1 =

As1
≤ 0.02
bw d

SAFE
0
(EC2 6.4.4(1))
(EC2 6.2.2(1))

Area of reinforcement at the face of column for design strip are as follows:
For CEN Default, Norway, Slovenia and Sweden:
A s in Strip Layer A = 9204.985 mm2
A s in Strip Layer B = 8078.337 mm2
Average A s = ( 9204.985 + 8078.337 ) 2 = 8641.661 mm2

ρ 1 = 8641.661 ( 8000 • 218 ) = 0.004955 ≤ 0.02
For Finland, Singapore and UK:
A s in Strip Layer A = 9319.248 mm2
A s in Strip Layer B = 8174.104 mm2
Average A s = ( 9319.248 + 8174.104 ) 2 = 8746.676 mm2

ρ 1 = 8746.676 ( 8000 • 218 ) = 0.005015 ≤ 0.02
For Denmark:
A s in Strip Layer A = 9606.651 mm2
A s in Strip Layer B = 8434.444 mm2
Average A s = ( 9606.651 + 8434.444 ) 2 = 9020.548 mm2

ρ 1 = 9020.548 ( 8000 • 218 ) = 0.005172 ≤ 0.02

EXAMPLE EUROCODE 2-04 RC-PN-001 - 5

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For CEN Default, Denmark, Norway, Singapore, Slovenia, Sweden and UK:

ν min = 0.035k 3 2 f ck 1 2 = 0.035 (1.9578 )

3/2

( 30 )

1/2

= 0.525 N/mm2

For Finland:

ν min = 0.035k 2/3 f ck1 2 = 0.035 (1.9578 )

2/3

( 30 )

1/2

= 0.3000 N/mm2

For CEN Default, Norway, Slovenia and Sweden:
vRd ,c = 0.12 • 1.9578 (100 • 0.004955 • 30 )

13

+ 0  = 0.5777 N/mm2

For Finland, Singapore, and UK:
13
vRd ,c = 0.12 • 1.9578 (100 • 0.005015 • 30 ) + 0  = 0.5796 N/mm2

For Denmark:
13
vRd ,c = 0.124 • 1.9578 (100 • 0.005015 • 30 ) + 0  = 0.606 N/mm2

For CEN Default, Norway, Slovenia and Sweden:
Shear Ratio
=

v max
=
vRd ,c

1.092
= 1.90
0.5777

For Finland, Singapore and UK:
Shear Ratio
=

v max
=
vRd ,c

1.092
= 1.90
0.5796

For Denmark:
Shear Ratio
=

v max
=
vRd ,c

EXAMPLE EUROCODE 2-04 RC-PN-001 - 6

1.092
= 1.81
0.606



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