Contents Problem 1 006
Problem 1-006 Problem 1-006
User Manual: Problem 1-006
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Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 FRAME - NON-PRISMATIC SECTIONS AND AUTOMATIC FRAME SUBDIVISION EXAMPLE DESCRIPTION This example tests the SAP2000 non-prismatic frame section property. In SAP2000 the axial (A), torsion (J), weight, and mass properties can vary linearly, and the bending property (I) variation can be linear, parabolic or cubic. The variation of the moment of inertia is defined in SAP2000 as follows: L I1 I2 x x I ( x) = (I11/ n ) 1 − + L (I ) Lx 1/ n 2 n where, n = 1 for linear variation, n = 2 for parabolic variation, and n = 3 for cubic variation, The example model consists of a complex, non-prismatic frame section that is made up of four segments, assigned to a cantilever beam, and subjected to seven load cases, each with a different type of loading. An applicable deformation component at the free end of the cantilever is compared with independent hand calculated results for each load case. Important Note: Only bending and axial deformations are considered in the analysis. Shear deformations are ignored. In SAP2000 this is achieved by setting the property modification factor for shear area to 0. This example also tests the frame automatic subdivide feature of SAP2000. The automatic frame subdivide option internally divides the frame object into a userspecified number of elements for the analysis. The analysis results are combined and reported for the entire frame object, not the subdivided elements. In this example two models are run. Model A has no automatic subdivision. Model B has automatic subdivision that divides the frame object up into 10 equal length elements. The results are compared for each model. EXAMPLE 1-006 - 1 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 GEOMETRY, PROPERTIES AND LOADING 144" Seg. 2 Seg. 3 Seg. 4 Material Properties E = 3,600 k/in2 ν = 0.2 G = 1,500 k/in2 Unit weight = 0.15 k/ft3 FSec 2 Seg. 1 FSec 1 FSec 1 36" FSec 2 FSec 3 36" FSec 3 FSec 2 Y 36" FSec 4 Z 36" X Segment Definitions Segment 1 Segment 2 Segment 3 Segment 4 Start Section FSec4 FSec2 FSec3 FSec1 End Section FSec3 FSec2 FSec1 FSec2 36 36 36 36 Axial (A) Variation Linear Constant Linear Linear Bending (I33) Variation Linear Constant Parabolic Cubic Bending (I22) Variation Linear Constant Parabolic Cubic Torsion (J) Variation Linear Constant Linear Linear Length, in EXAMPLE 1-006 - 2 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 Section Properties FSec1 FSec2 FSec3 FSec4 Width b, in 12 12 12 12 Depth d, in 12 18 24 30 Area A, in2 144 216 288 360 Bending I33, in4 1728 5832 13824 27000 Bending I22, in4 1728 2592 3456 4320 2,920.32 6,085.12 9,492.12 12,934.73 Torsion J, in4 Loading Load Case Load Type Value 1 Self weight Not Applicable 2 Fx at free end (axial) 500 k 3 Fy at free end 5k 4 Fz at free end -5 k 5 Mx at free end (torsion) 5,000 k-in 6 My at free end 5,000 k-in 7 Mz at free end 5,000 k-in EXAMPLE 1-006 - 3 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 TECHNICAL FEATURES OF SAP2000 TESTED Structural behavior of a non-prismatic frame section Self weight calculations Linear variation of section area Linear, parabolic and cubic variation of moment of inertia Linear variation of section torsional constant Automatic frame subdivision RESULTS COMPARISON Independent results are hand calculated using the unit load method described on page 244 in Cook and Young 1985. Results for Model A (With No Automatic Subdivision) Load Case Output Parameter SAP2000 Independent Percent Difference 1 My (fixed end)k-in -184.950 -184.950 0% 2 Ux (free end) in 0.09087 0.09087 0% 3 Uy (free end) in 0.43120 0.43120 0% 4 Uz (free end) in -0.14335 -0.14335 0% 5 Rx (free end) rad 0.07987 0.07987 0% 6 Ry (free end) rad 0.03742 0.03742 0% 7 Rz (free end) rad 0.07634 0.07634 0% EXAMPLE 1-006 - 4 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 Results for Model B (With Automatic Subdivision into Ten Elements) Load Case Output Parameter SAP2000 Independent Percent Difference 1 My (fixed end)k-in -184.950 -184.950 0% 2 Ux (free end) in 0.09087 0.09087 0% 3 Uy (free end) in 0.43120 0.43120 0% 4 Uz (free end) in -0.14335 -0.14335 0% 5 Rx (free end) rad 0.07987 0.07987 0% 6 Ry (free end) rad 0.03742 0.03742 0% 7 Rz (free end) rad 0.07634 0.07634 0% COMPUTER FILE: Example 1-006a, Example 1-006b CONCLUSION The SAP2000 results show an exact match with the independent results for both models A and B. EXAMPLE 1-006 - 5 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 HAND CALCULATION EXAMPLE 1-006 - 6 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 - 7 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 - 8 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 - 9 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 - 10 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 - 11 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 - 12 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 - 13 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 - 14 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 - 15 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 - 16 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 - 17 Software Verification PROGRAM NAME: REVISION NO.: SAP2000 0 EXAMPLE 1-006 - 18
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