CSA A23.3 04 PT SL Example 001

User Manual: CSA A23.3-04 PT-SL Example 001

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CSA 23.3-04 PT-SL EXAMPLE 001
Post-Tensioned Slab Design
PROBLEM DESCRIPTION
The purpose of this example is to verify the slab stresses and the required area of
mild steel strength reinforcing for a post-tensioned slab.
A one-way simply supported slab is modeled in ETABS. The modeled slab is 254
mm thick by 914 mm wide and spans 9754 mm as shown in shown in Figure 1.
Prestressing tendon, Ap
Mild Steel, As

229 mm
254 mm
25 mm

Length, L = 9754 mm

914 mm

Section

Elevation

Figure 1 One-Way Slab

A 254-mm-wide design strip is centered along the length of the slab and has been
defined as an A-Strip. B-strips have been placed at each end of the span
CSA 23.3-04 PT-SL EXAMPLE 001 - 1

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perpendicular to Strip-A (the B-Strips are necessary to define the tendon profile).
A tendon with two strands, each having an area of 99 mm2, has been added to the
A-Strip. The self weight and live loads were added to the slab. The loads and posttensioning forces are as follows:
Loads:

Dead = self weight,

Live = 4.788 KN/m2

The total factored strip moments, required area of mild steel reinforcement, and
slab stresses are reported at the midspan of the slab. Independent hand calculations
have been compared with the ETABS results and summarized for verification and
validation of the ETABS results.
GEOMETRY, PROPERTIES AND LOADING
Thickness
Effective depth
Clear span

T, h =
d
=
L =

254
229
9754

mm
mm
mm

Concrete strength
Yield strength of steel
Prestressing, ultimate
Prestressing, effective
Area of Prestress (single strand)
Concrete unit weight
Modulus of elasticity
Modulus of elasticity
Poisson’s ratio

f 'c
fy
fpu
fe
Ap
wc
Ec
Es


=
=
=
=
=
=
=
=
=

30
400
1862
1210
198
23.56
25000
200,000
0

MPa
MPa
MPa
MPa
mm2
KN/m3
N/mm3
N/mm3

Dead load
Live load

wd
wl

=
=

self
4.788

KN/m2
KN/m2

TECHNICAL FEATURES OF ETABS TESTED
 Calculation of the required flexural reinforcement
 Check of slab stresses due to the application of dead, live, and post-tensioning
loads.

CSA 23.3-04 PT-SL EXAMPLE 001 - 2

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RESULTS COMPARISON
Table 1 shows the comparison of the ETABS total factored moments, required
mild steel reinforcing, and slab stresses with the independent hand calculations.
Table 1 Comparison of Results
FEATURE TESTED
Factored moment,
Mu (Ultimate) (kN-m)
Area of Mild Steel req’d,
As (sq-cm)
Transfer Conc. Stress, top
(D+PTI), MPa
Transfer Conc. Stress, bot
(D+PTI), MPa
Normal Conc. Stress, top
(D+L+PTF), MPa
Normal Conc. Stress, bot
(D+L+PTF), MPa
Long-Term Conc. Stress,
top (D+0.5L+PTF(L)), MPa
Long-Term Conc. Stress,
bot (D+0.5L+PTF(L)), MPa

INDEPENDENT
RESULTS

ETABS
RESULTS

DIFFERENCE

159.4

159.4

0.00%

16.25

16.33

0.49%

5.058

5.057

-0.02%

2.839

2.839

0.00%

10.460

10.467

0.07%

8.402

8.409

0.08%

7.817

7.818

0.01%

5.759

5.760

0.02%

COMPUTER FILE: CSA A23.3-04 PT-SL EX001.EDB
CONCLUSION
The ETABS results show an exact comparison with the independent results.

CSA 23.3-04 PT-SL EXAMPLE 001 - 3

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HAND CALCULATIONS:
Design Parameters:
Mild Steel Reinforcing
fcu = 30MPa
fy = 400MPa

Post-Tensioning
fpu = 1862 MPa
fpy = 1675 MPa
Stressing Loss = 186 MPa
Long-Term Loss = 94 MPa
fi = 1490 MPa
fe = 1210 MPa

c  0.65 , S  0.85
1 = 0.85 – 0.0015f'c  0.67 = 0.805
1 = 0.97 – 0.0025f'c  0.67 = 0.895

Prestressing tendon, Ap
Mild Steel, As

229 mm
254 mm
25 mm

Length, L = 9754 mm
Elevation

914 mm

Section

Loads:
Dead, self-wt = 0.254 m x 23.56 kN/m3 = 5.984 kN/m2 (D) x 1.25 = 7.480 kN/m2 (Du)
Live,
= 4.788 kN/m2 (L) x 1.50 = 7.182 kN/m2 (Lu)
Total = 10.772 kN/m2 (D+L)
= 14.662 kN/m2 (D+L)ult

 =10.772 kN/m2 x 0.914m = 9.846 kN/m,  u = 16.039 kN/m2 x 0.914m = 13.401 kN/m
Ultimate Moment, M U 

CSA 23.3-04 PT-SL EXAMPLE 001 - 4

wl12
= 13.401 x (9.754)2/8 = 159.42 kN-m
8

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Ultimate Stress in strand, f pb  f pe 

cy 

ETABS
0

8000
 d p  cy 
lo

 p Ap f pr  s As f y 0.9 197 1347   0.85 1625  400 

 61.66 mm
0.805  0.65  30.0  0.895  914 
1c f 'c 1b

f pb  1210 

8000
 229  61.66   1347 MPa
9754

Depth of the compression block, a, is given as:
Stress block depth, a  d  d 2 

2M *
 1 f 'c c b

 0.229  0.2292 

2 159.42 
 55.18
0.805  30000  0.65  0.914 

Ultimate force in PT, Fult , PT  AP ( f PS )  197 1347  1000  265.9 kN
Ultimate moment due to PT,

a
55.18 


M ult , PT  Fult , PT  d     265.9  0.229 
  0.85   45.52 kN-m
2
2 


Net Moment to be resisted by As, M NET  MU  M PT
 159.42  45.52  113.90 kN-m
The area of tensile steel reinforcement is then given by:
As 

M NET
=
0.87 f y z

113.90
1e6   1625 mm 2
55.18


0.87  400   229 

2 


Check of Concrete Stresses at Midspan:
Initial Condition (Transfer), load combination (D+PTi) = 1.0D+0.0L+1.0PTI

Tendon stress at transfer = jacking stress  stressing losses = 1490  186 = 1304 MPa
The force in the tendon at transfer, = 1304 197.4  1000  257.4 kN

CSA 23.3-04 PT-SL EXAMPLE 001 - 5

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Moment due to dead load, M D  5.984  0.914  9.754  8  65.04 kN-m
2

Moment due to PT, M PT  FPTI (sag)  257.4 102 mm  1000  26.25 kN-m
F
M  M PT
257.4
65.04  26.23
Stress in concrete, f  PTI  D


0.254(0.914)
0.00983
A
S
where S = 0.00983m3

f  1.109  3.948 MPa
f  5.058(Comp) max, 2.839(Tension) max
Normal Condition, load combinations: (D+L+PTF) = 1.0D+1.0L+1.0PTF

Tendon stress at normal = jacking  stressing  long-term = 1490  186  94 = 1210 MPa
The force in tendon at normal, = 1210 197.4  1000  238.9 kN
Moment due to dead load, M D  5.984  0.914  9.754  8  65.04 kN-m
2

Moment due to live load, M L  4.788  0.914  9.754  8  52.04 kN-m
2

Moment due to PT,

M PT  FPTI (sag)  238.9 102 mm  1000  24.37 kN-m

Stress in concrete for (D+L+PTF),
F
M
 M PT
238.8
117.08  24.37
f  PTI  D  L


A
S
0.254  0.914 
0.00983
f  1.029  9.431
f  10.460(Comp) max, 8.402(Tension) max
Long-Term Condition, load combinations: (D+0.5L+PTF(L)) = 1.0D+0.5L+1.0PTF

Tendon stress at normal = jacking  stressing  long-term = 1490  186  94 = 1210 MPa
The force in tendon at normal, = 1210 197.4  1000  238.9 kN
Moment due to dead load, M D  5.984  0.914  9.754  8  65.04 kN-m
2

Moment due to live load, M L  4.788  0.914  9.754  8  52.04 kN-m
2

Moment due to PT,

M PT  FPTI (sag)  238.9 102 mm  1000  24.37 kN-m

Stress in concrete for (D+0.5L+PTF(L)),
M
 M PT
F
238.9
91.06  24.33
f  PTI  D  0.5 L


0.254  0.914 
0.00983
A
S
f  1.029  6.788
f  7.817(Comp) max, 5.759(Tension) max
CSA 23.3-04 PT-SL EXAMPLE 001 - 6



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